Velocity and Acceleration of an Object

Velocity and Acceleration of an Object#

If the velocity of an object in one-dimensional motion is given by \(v(t) = \) \(-6t^3 - 6t^2 + 6t\), where the units of \(v\) are in \(m/s\) and of \(t\) are in seconds,

Part 1#

The velocity and acceleration of the object at \(t = \) 6.3 \(s\) are:

Answer Section#

  • \(v = \) -1700.0 \(m/s\), \(a = \) -784.0 \(m/s^2\)

  • \(v = \) -1700.0 \(m/s\), \(a = \) 0 \(m/s^2\)

  • \(v = \) -1700.0 \(m/s\), \(a = \) 9.81 \(m/s^2\)

  • \(v = \) 6.3 \(m/s\), \(a = \) -392.0 \(m/s^2\)

  • \(v = \) -1700.0 \(m/s\), \(a = \) 784.0 \(m/s^2\)

  • \(v = \) -1700.0 \(m/s\), \(a = \) -1570.0 \(m/s^2\)

Attribution#

Problem is licensed under the CC-BY-NC-SA 4.0 license.
The Creative Commons 4.0 license requiring attribution-BY, non-commercial-NC, and share-alike-SA license.

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